Question #151518
Find the spherical coordinates of the point whose coordinates are
1) (1, 1, √6)
2) (-2, 2√3, 4)
3) (-√3, 1, -2)
4) (4,-4√3, 6)
1
Expert's answer
2020-12-17T18:40:12-0500

We remind the expressions of spherical coordinates :

ρ=x2+y2+z2\rho = \sqrt{x^2+y^2+z^2}

θ=arccos(zρ)\theta = \arccos(\frac{z}{\rho})

ϕ\phi such that x=ρsin(θ)cos(ϕ),y=ρsin(θ)sin(ϕ)x=\rho \sin(\theta) \cos(\phi), y=\rho\sin(\theta)\sin(\phi)

Therefore we have :

  1. (ρ,θ,ϕ)=(22,π6,π4)(\rho,\theta,\phi) = (2\sqrt{2}, \frac{\pi}{6}, \frac{\pi}{4})
  2. (42,π4,2π3)(4\sqrt{2}, \frac{\pi}{4}, \frac{2\pi}{3})
  3. (22,3π4,5π6)(2\sqrt{2}, \frac{3\pi}{4}, \frac{5\pi}{6})
  4. (10,arccos(35),π3)(10, \arccos(\frac{3}{5}), -\frac{\pi}{3})

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