Question #144511
Given that \\(R=sin ¡t i+cos ¡t j+tk\\), find \\( (d^2 R)/(dt^2 )\\).
1
Expert's answer
2020-11-17T17:45:07-0500

First of all let us notice the fact that the basis vectors of R3(i,j,k)\mathbb{R}^3 (i, j, k) are constant (as opposed to local vectors er,eθ,eze_r,e_\theta, e_z of the cylindrical coordinates base, for example). Therefore the derivation of R(t)R(t) comes down to deriving every coordinate. Secondly, let us write R(t)R(t) as a vector for more obviousness:

R(t)=(sin(a^t)cos(a^t)t)R(t)=\begin{pmatrix}\sin(\hat{a}t) \\ \cos(\hat{a}t) \\ t\end{pmatrix}

Now let's calculate the first and then the second derivative:

ddtR(t)=(a^cos(a^t)a^sin(a^t)1)\frac{d}{dt} R(t) = \begin{pmatrix} \hat{a}\cos(\hat{a}t) \\ -\hat{a}\sin(\hat{a}t) \\ 1 \end{pmatrix}

d2dt2R(t)=(a^2sin(a^t)a^2cos(a^t)0)\frac{d^2}{dt^2} R(t) = \begin{pmatrix} -\hat{a}^2 \sin(\hat{a}t) \\ -\hat{a}^2 \cos(\hat{a}t) \\ 0 \end{pmatrix}


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