Ao = union of open subsets of A. Hence Ao={1,2}∪{1}∪{∅}={1,2}. ext(A)= union of open sets disjoint from A=∅ since every nonempty set contains 1. b(A)= A∖Ao=N∖{1,2}. since ext(A) is empty, closure of A is the entire space.
Bo= ∅ since all non-empty open sets contain 1. ext(B)==∅∪{1}∪{1,2}∪{1,2,3}∪{1,2,3,4} ={1,2,3,4}. b(B)= B∖Bo=B. Since {1,2,3,4}
is the largest open set disjoint from B. Hence B=N∖{1,2,3,4}.
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