▽(f)=<fx,fy>=<x2,−y2>\bigtriangledown (f) =<f_{x},f_{y}>=<\dfrac{x}{2},-\dfrac{y}{2}>▽(f)=<fx,fy>=<2x,−2y> Hence for sketching, the vector with initial point (x,y)(x,y)(x,y)points parallel to the vector (x2,−y2).(\frac{x}{2},-\frac{y}{2}).(2x,−2y). So the gradient looks like
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments