Question #137813
Sketch the level curves f−1(c) for the following functions: (a) f(x,y) = x2 + y2, c = 0,1,2,3,4.
1
Expert's answer
2020-10-12T18:13:38-0400

Given, f:R2Rf:\mathbb{R}^2\rightarrow \mathbb{R} is a smooth map such that ff is defined as below

f(x,y)=x2+y2f(x,y)=x^2+y^2

Now, when c=0 then


f(x,y)=0    x2+y2=0    x=y=0f(x,y)=0\implies x^2+y^2=0\implies x=y=0

Thus, f1(c=0)={(0,0)}f^{-1}(c=0)=\{(0,0)\} .

Now, for positive cc ,


f(x,y)=c=x2+y2f(x,y)=c=x^2+y^2

Represents locus of radius c\sqrt{c} and center is (0,0), thus


f1(c)={(x,y)R2:f(x,y)=c}f^{-1}(c)=\{(x,y)\in \mathbb{R}^2:f(x,y)=c\}

is the set of points on the circle mentioned above.

Thus, level curves for c=0,1,2,3,4 will be



Where, origin is f1(0)f^{-1}(0) , Blue, Green, Violet and black circles are respectively f1(1),f1(2),f1(3)&f1(4)f^{-1}(1),f^{-1}(2),f^{-1}(3)\&f^{-1}(4) respectively.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS