a)
P(z>z′)=0.15→P(z<z′)=0.85 From z-table:
z′=1.04
x′=20+(1.04)4=24.16 b)
P(z>z′)=0.75→P(z<z′)=0.25 From z-table:
z′=−0.67
x′=20+(−0.67)4=17.32 c)
P(z<−z′)=0.2,P(z>z′)=0.2 From z-table:
P(z<−0.84)=0.2005
z′=0.84
x1′=20+(−0.84)4=16.64
x2′=20+(0.84)4=23.36 d)
P(z<z′)=0.25 Thus, this is the same value as in the part b).
x′=17.32
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