Question #98595
The heights of 2-year-old children are normally distributed with a mean of 32 inches and
a standard deviation of 1.5 inches. Pediatricians regularly measure the heights of toddlers
to determine whether there is a problem. There may be a problem when a child is in the
top or bottom 5% of heights. [10 Marks]
a. Determine the heights of 2-year-old children that could be a problem. [4 Marks]
b. Find the probability of these events:
(i) A 2-year-old child is taller than 36 inches [2 Marks]
(ii) A 2-year-old child is shorter than 34 inches [2 Marks]
(iii) A 2-year-old child is between 30 and 33 inches tall [2 Marks]
1
Expert's answer
2019-11-13T12:01:59-0500

a. P(Z<z)=0.05z=1.6451.645=x321.5x=29.5.P(Z<z)=0.05\to z=-1.645\to -1.645=\frac{x-32}{1.5}\to x=29.5.

P(Z>z)=0.05z=1.6451.645=x321.5x=34.5P(Z>z)=0.05\to z=1.645\to 1.645=\frac{x-32}{1.5}\to x=34.5

The heights less than 29.5 in and greater than 34.5 in could be a problem.


b.

(i) P(X>36)=P(Z>36321.5)=P(Z>2.67)=0.0038.P(X>36)=P(Z>\frac{36-32}{1.5})=P(Z>2.67)=0.0038.

(ii) P(X<34)=P(Z<34321.5)=P(Z<1.33)=0.9082.P(X<34)=P(Z<\frac{34-32}{1.5})=P(Z<1.33)=0.9082.

(iii)

P(30<X<33)=P(30321.5<Z<33321.5)==P(1.33<Z<0.67)=0.6568.P(30<X<33)=P(\frac{30-32}{1.5}<Z<\frac{33-32}{1.5})=\\=P(-1.33<Z<0.67)=0.6568.



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Comments

pragna
15.07.21, 18:01

A very clear and good work which is easy to understand.

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