Question #98527
The average number of defects per 20 m2 area of a floor mat produced by a local company is two. A room has an area of 100 m2 and uses the same floor mat as described above.
i) Find the probability that there are at most two defects in a randomly selected 20 m2 of the floor mat.
ii) Find the probability that the floor mat contains at least three defects in the room.
1
Expert's answer
2019-11-13T11:32:19-0500

a) We need to use a Poisson distribution with λ=2\lambda=2


P(k2)=P(k=0)+P(k=1)+P(k=2)P(k\leq 2 )=P(k=0)+P(k=1)+P(k=2)

P(k2)=20e20!+21e21!+22e22!P(k\leq 2 )=2^0\frac{e^{-2}}{0!}+2^1\frac{e^{-2}}{1!}+2^2\frac{e^{-2}}{2!}

P(k2)=e2(1+2+2)=5e2=0.6767P(k\leq 2 )=e^{-2}(1+2+2)=5e^{-2}=0.6767

b) We need to use a Poisson distribution with λ=210020=2(5)=10\lambda'=2\frac{100}{20}=2(5)=10

P(k3)=1P(k2)P(k\geq 3 )=1-P(k\leq 2 )

P(k2)=100e100!+101e101!+102e102!P(k\leq 2 )=10^0\frac{e^{-10}}{0!}+10^1\frac{e^{-10}}{1!}+10^2\frac{e^{-10}}{2!}

P(k2)=e10(1+10+50)=61e10=0.0028P(k\leq 2 )=e^{-10}(1+10+50)=61e^{-10}=0.0028


P(k3)=10.0028=0.9972P(k\geq 3 )=1-0.0028=0.9972


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