a) We need to use a Poisson distribution with λ=2
P(k≤2)=P(k=0)+P(k=1)+P(k=2)
P(k≤2)=200!e−2+211!e−2+222!e−2
P(k≤2)=e−2(1+2+2)=5e−2=0.6767 b) We need to use a Poisson distribution with λ′=220100=2(5)=10
P(k≥3)=1−P(k≤2)
P(k≤2)=1000!e−10+1011!e−10+1022!e−10
P(k≤2)=e−10(1+10+50)=61e−10=0.0028
P(k≥3)=1−0.0028=0.9972
Comments