"Standard\\,error=\\sqrt{\\frac{p\u00d7(1-p)}{n}}=\\sqrt{\\frac{0.72\u00d70.28}{100}}=0.045"
"z-value\\,for\\,95\\%\\,confidence=1.96"
"Upper\\,bound=p+z\u00d7SE=0.72+1.96\u00d70.045=0.808"
"Lower\\,bound=p-z\u00d7SE=0.72-1.96\u00d70.045=0.632"
Answer: 72%±4.5%
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Dear Bryan, please use the panel for submitting new questions.
forty randomly selected students were asked if they smoke cigarettes regularly, 9 of them said they did find a 95% confidence interval for the true proportion of students who smoke regularly
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