Question #98204
Hi,I’m struggling with counting principle in probability.Please explain it to me.All the rules of counting principles,why do we sometimes divide and sometimes multiply together and what does factorial mean?please help me understand each rule please?
1
Expert's answer
2019-11-11T09:47:23-0500

Multiplication Rule

If one event can occur in mm ways, a second event in nn ways and a third event in r,r, then the three events can occur in m×n×rm\times n\times r ways.

Repetition of an Event

If one event with nn outcomes occurs rr times with repetition allowed, then the number of ordered arrangements is nr.n^r.

Arrangements or Permutations

Distinctly ordered sets are called arrangements or permutations (order matters, no repetition). 

The factorial is computed by the formula n!=12n.n!=1\cdot 2 \cdot \dots \cdot n.

The number of permutations of size kk that can be formed from the nn individuals or objects in a group will be denoted by Pn,k.P_{n,k}.

The number of permutations of nn objects taken kk at a time is given by:


Pn,k=n!(nk)!P_{n,k}={n! \over (n-k)!}


Permutations with indistinguishable objects

If the nn objects are all distinguishable there are n!n! permutations.

Dividing n!n! by n1!n_1! gives the number of permutations of nn objects with n1n_1 of them being identical.

Repeating, to identify n2n_2 objects of type 2, …, nkn_k objects of type k,k, gives


n!n1!n2!...nk!{n! \over n_1!n_2!...n_k!}

as the result.

Example

If we have nn elements of which xx are alike of one kind, yy are alike of another kind, zz are alike of another kind, then the number of ordered selections or permutations is given by:


n!x!y!z!{n! \over x!y!z!}

An unordered subset is called a combination. One way to denote the number of combinations is

Cn,k.C_{n,k}.


Definition of combination without repetition

Let a1,a2,...,ana_1,a_2,...,a_n be nn objects. A simple combination (or combination without repetition) of kk objects from the nn objects is one of the possible ways to form a set containing kk of the nn objects.

To form a valid set, any object can be chosen only once. Furthermore, the order in which the objects are chosen does not matter.


Cn,k=Pn,kk!=n!k!(nk)!=(nk)C_{n,k}={P_{n,k} \over k!}={n! \over k!(n-k)!}=\binom{n}{k}


Definition of combination with repetition

The difference between a multiset and a set is the following: the same object is allowed to appear more than once in the list of members of a multiset, while the same object is allowed to appear only once in the list of members of an ordinary set.

Let a1,a2,...,ana_1,a_2,...,a_n be nn objects. A  combination with repetition of kk objects from the nn objects is one of the possible ways to form a multiset containing kk of the nn objects.


Cn,k=Cn+k1,k=(n+k1k)=(n+k1)!k!(n+k1k)!=C'_{n,k}=C_{n+k-1,k}=\binom{n+k-1}{k}={(n+k-1)! \over k!(n+k-1-k)!}==(n+k1)!k!(n1)!={(n+k-1)! \over k!(n-1)!}

Permutation with repetition (Use permutation formulas when order matters in the problem.

nrn^r

Where nn is the number of things to choose from, and you choose rr of them. 


Permutation without repetition

(Use permutation formulas when order matters in the problem.)


Pn,k=n!(nk)!P_{n,k}={n! \over (n-k)!}

Where nn is the number of things to choose from, and you choose kk of them. 


Combination with repetition

(Use combination formulas when order doesn’t matter in the problem.)


Cn+k1,k=(n+k1k)=(n+k1)!k!(n1)!C_{n+k-1,k}=\binom{n+k-1}{k}={(n+k-1)! \over k!(n-1)!}

Where nn is the number of things to choose from, and you choose kk of them. 


Combination without repetition

(Use combination formulas when order doesn’t matter in the problem.)


Cn,k=Pn,kk!=n!k!(nk)!=(nk)C_{n,k}={P_{n,k} \over k!}={n! \over k!(n-k)!}=\binom{n}{k}

Where nn is the number of things to choose from, and you choose kk of them.


Putting objects into boxes

There are

n!n1!n2!...nk!{n! \over n_1!n_2!...n_k!}

ways to put nn distinguishable objects into kk boxes, so that the iith box contains nin_i objects.


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