The first step is calculating the sample space S= {2, 3, ,3 ,4,4,4 ,5,5,5,5,6,6,6,6,6,7,7,7,7,7,7,8,8,8,8,8,9,9,9,9,10,10,10,11,11,12}
count the frequency of each possible outcome and divide with total count n =36 to find PDF then calculate CDF for each X by adding the current and all preceding PDFs.
X PDF CDF
2 361 361
3 181 121
4 121 61
5 91 185
6 365 125
7 61 127
8 365 1813
9 91 65
10 121 1211
11 181 3635
12 361 1
The most likely sum is 7 it has the highest PDF .
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