Question #97996
For a random sample of 10 men, the mean head circumference is = 57.3 cm and the sample standard deviation xis s = 2 cm. What is the standard error of the mean?
1
Expert's answer
2019-11-05T12:20:23-0500

Let X=X= the mean head circumference. If XB(n,p),X\sim B(n, p), then


E(X)=μX=np,σX2=np(1p)E(X)=\mu_X=np, \sigma_{X}^2 =np(1-p)

Var(1ni=1nXi)=1n2(i=1nVar(Xi))=Var({1 \over n}\displaystyle\sum_{i=1}^nX_i)={1 \over n^2}\bigg(\displaystyle\sum_{i=1}^nVar(X_i)\bigg)=

=1n2(nσX2)=σX2n=p(1p)={1 \over n^2}(n\sigma_{X}^2)={\sigma_X^2 \over n} =p(1-p)

The standard error of the mean


SE=σX2n=σXnSE=\sqrt{{\sigma_X^2 \over n}}={\sigma_X \over \sqrt{n}}

Given that


E(X)=μX=np=57.3 cm,σX=2 cm,n=10E(X)=\mu_X=np=57.3\ cm,\sigma_X=2\ cm, n=10

Then


SE=σXn=2 cm100.6325cmSE={\sigma_X \over \sqrt{n}}={2\ cm \over \sqrt{10}}\approx0.6325 cm

SE=0.6325 cmSE=0.6325\ cm

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