Let "X=" the mean head circumference. If "X\\sim B(n, p)," then
"Var({1 \\over n}\\displaystyle\\sum_{i=1}^nX_i)={1 \\over n^2}\\bigg(\\displaystyle\\sum_{i=1}^nVar(X_i)\\bigg)="
"={1 \\over n^2}(n\\sigma_{X}^2)={\\sigma_X^2 \\over n} =p(1-p)"
The standard error of the mean
Given that
Then
"SE=0.6325\\ cm"
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