Question #9762

3.assume the random variable x is normally distributed with mean (wierd character)..(u)=90 and standard deviation o=4 find the indicated probability P(78<x<88) (round="" to="" four="" decimal="" places="" as="" needed)

Expert's answer

3. assume the random variable xx is normally distributed with mean (wierd character).(u)=90 and standard deviation σ=4\sigma = 4 find the indicated probability

P(78<x<88) (round="" to="" decimal="" places" as="" needed) please show your work


P(78<x<88)=P(78904<x904<88904)=P(3<x904<0.5)=by CLT (Central Limit Theorem)=\mathrm{P}(78 < \mathrm{x} < 88) = \mathrm{P}\left(\frac{78 - 90}{4} < \frac{\mathrm{x} - 90}{4} < \frac{88 - 90}{4}\right) = \mathrm{P}\left(-3 < \frac{\mathrm{x} - 90}{4} < 0.5\right) = \text{by CLT (Central Limit Theorem)} =F(0.5)F(3)=F(3)F(0.5)=0.99860.6915=0.3071\begin{array}{l} \mathrm{F}(-0.5) - \mathrm{F}(-3) = \mathrm{F}(3) - \mathrm{F}(0.5) = 0.9986 - 0.6915 \\ = 0.3071 \\ \end{array}

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