Question #9760

12 people sit randomly on 20 seats in a row. What is the probability that each one of them has exactly one neighbour?

Expert's answer

12 people sit randomly on 20 seats in a row. What is the probability that each one of them has exactly one neighbour? Please show your work

There are 201920*19 Variants of each one of them has exactly one neighbor. (because there are 2 vacant places)

Total variants are C2012C_{20}^{12}

So P=2019/C2012P = 20*19 / C_{20}^{12}

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