Let "\\hat{p}" be the sample proportion.
When n is large and p is not close to zero or one, we can use the normal distribution to approximate the binomial.
The sampling distribution of "\\hat{p}" is normal.
The mean of the sampling distribution is "p."
The standard deviation of the sampling distribution (called the standard error) is
Given that "p=0.65, n=805"
a)
b)
Confidence Level 98%: "z^*-" value"=2.33"
Confidence interval for "p" is
"0.65\\pm 2.33\\times 0.016811\\approx0.65\\pm0.039"
"98\\%\\ CI=(0.611, 0.689)"
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