Question #97332
(b) Calculate the missing frequency from the data if the median is 50.
CI 10-20 20-30 30-40 40-50 50-60 60-70
f 2 8 6 ? 15 10
1
Expert's answer
2019-10-25T11:15:22-0400
ClassIntervalCIFrequencyfCumulativeFrequency102022203081030406164050f416+f450601531+f460701041+f4\begin{array}{c:c:c} \begin{matrix} Class \\ Interval\\ CI \end{matrix}& \begin{matrix} Frequency \\ f \end{matrix} &\begin{matrix} Cumulative \\ Frequency \end{matrix} \\ \hline 10-20 & 2 & 2 \\ \hdashline 20-30 & 8 & 10 \\ \hdashline 30-40 & 6 & 16\\ \hdashline 40-50 & f_4 & 16+f_4\\ \hdashline 50-60 & 15 & 31+f_4\\ \hdashline 60-70 & 10 & 41+f_4 \end{array}


Estimated Median=L+n2BG×wEstimated\ Median=L+{{n \over 2}-B \over G}\times w


where:

LL  is the lower class boundary of the group containing the median

nn  is the total number of values

BB  is the cumulative frequency of the groups before the median group

GG  is the frequency of the median group

ww is the group width

We have that n=2+8+6+f4+15+10=41+f4n=2+8+6+f_4+15+10=41+f_4


Median=50Median=50

The median lies in class interval CI=5060CI=50-60

L=50,n=41+f4,B=16+f4,G=15,w=10L=50, n=41+f_4, B=16+f_4,G=15,w=10


50=50+41+f42(16+f4)15×1050=50+{{41+f_4 \over 2}-(16+f_4) \over 15}\times 1041+f42(16+f4)=0{41+f_4 \over 2}-(16+f_4) =0


41+f4=32+2f441+f_4=32+2f_4

f4=9f_4=9

The missing frequency is 9.9.



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