μ = 10.5 , σ = 3.5 , n = 50 , x ˉ = 11.3 F o r m u l a t e t h e h y p o t h e s i s H 0 : μ = 10.5 H 1 : μ > 10.5 T h i s i s a o n e t a i l e d t e s t α = 0.05 S i n c e σ i s k n o w n w e a r e u s i n g t h e z t e s t 1 − 0.05 = 0.95 , f r o m z − t a b l e s w e h a v e 1.645 T h e z c r i t i c a l v a l u e ( s ) i s 1.645 z = x ˉ − μ σ n = 11.3 − 10.5 3.5 50 = 1.616 S i n c e t h e t e s t s t a t i s t i c s i s l e s s t h a n t h e c r i t i c a l v a l u e , t h a t i s 1.616 < 1.645 W e f a i l t o r e j e c t t h e t h e n u l l h y p o t h e s i s a n d c o n c l u d e t h a t t h e n e w m o d e l i s n o t f u e l e f f i c i e n t a s c o m p a r e d t o t h e o l d m o d e l w i t h a v e r a g e o f 10.5 k m p e r l i t r e a t 5 % l e v e l o f s i g n i f i c a n c e . \mu=10.5, \sigma=3.5, n=50, \bar{x} =11.3\\
Formulate\ the \ hypothesis\\
H_0:\mu=10.5\\
H_1:\mu>10.5\\
This \ is \ a\ one\ tailed\ test\\
\alpha=0.05\\
Since\ \sigma \ is \ known\ we\ are\ using\ the\ z\ test\\
1-0.05=0.95,\ from\ z-tables\ we \ have\ 1.645\\
The\ z\ critical\ value(s)\ is\ 1.645\\
z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}=\frac{11.3-10.5}{\frac{3.5}{\sqrt{50}}}=1.616\\
Since\ the\ test\ statistics\ is \,less \ than\ the\ critical\ value,\ that\ is\ 1.616\lt1.645\\
We\ fail\ to\ reject\ the\ the\ null\ hypothesis\ and\ conclude\ that\ the\ new\ model\ is\ not\ fuel\ efficient\\
as\ compared\ to\ the\ old\ model\ with\ average\ of\ 10.5km\ per\ litre\ at\ 5\%\ level\ of significance. μ = 10.5 , σ = 3.5 , n = 50 , x ˉ = 11.3 F or m u l a t e t h e h y p o t h es i s H 0 : μ = 10.5 H 1 : μ > 10.5 T hi s i s a o n e t ai l e d t es t α = 0.05 S in ce σ i s kn o w n w e a re u s in g t h e z t es t 1 − 0.05 = 0.95 , f ro m z − t ab l es w e ha v e 1.645 T h e z cr i t i c a l v a l u e ( s ) i s 1.645 z = n σ x ˉ − μ = 50 3.5 11.3 − 10.5 = 1.616 S in ce t h e t es t s t a t i s t i cs i s l ess t han t h e cr i t i c a l v a l u e , t ha t i s 1.616 < 1.645 W e f ai l t o re j ec t t h e t h e n u ll h y p o t h es i s an d co n c l u d e t ha t t h e n e w m o d e l i s n o t f u e l e ff i c i e n t a s co m p a re d t o t h e o l d m o d e l w i t h a v er a g e o f 10.5 km p er l i t re a t 5% l e v e l o f s i g ni f i c an ce .
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