1)P(N∩E)=P(E)⋅P(N∣E)=0.25⋅0.95=8019
2)P(N)=P(N∩(E∪S))=P((N∩E)∪(N∩S)) . Since (N∩E)∩(N∩S)=N∩(E∩S)=N∩∅=∅ , we have
P((N∩E)∪(N∩S))=P(N∩E)+P(N∩S)=
P(E)P(N∣E)+P(S)P(N∣S)=
=0.25⋅0.95+0.75⋅0.8=8067
3)P(E∣N)=P(N)P(E∩N)=6719
Answer: 1)8019 2)8067 3)6719
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