a. P(GasshortageORMechanicalproblem)=10025+20−15=0.3.
b. P(Mechanicalproblem∣Gasshortage)=2515=0.6.
c. P(GasshortageANDMechanicalproblem)=10015=0.15.
P(Gasshortage)∗P(Mechanicalproblem)=10025∗10020=0.05.
Since 0.15=0.05, gas shortage and mechanical problem are not independent.
Comments