Question #94777

A student calculated the mean of five numbers as 45.3. while checking his work he discovered that his total was short by 20.5. What is the correct mean of the numbers?


1
Expert's answer
2019-09-19T11:18:11-0400
mean=μ=Total sumnmean=\mu={Total \ sum \over n}

Given that

n=5,mean=μ=45.3n=5, mean=\mu= 45.3

New Total sum=Total sum+20.5New\ Total\ sum=Total\ sum+20.5


new mean=μnew=New Total sumnnew\ mean=\mu_{new}={New\ Total \ sum \over n}

new mean=μnew=Total sum+20.55=μ+4.1=new\ mean=\mu_{new}={Total\ sum+20.5 \over 5}=\mu+4.1==45.3+4.1=49.4=45.3+4.1=49.4

The correct mean of the numbers is 49.449.4


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