Let X be the number of individuals in the TG control group.
Given:
"\\hat{p_2}=15.8\\%=0.158""n_2=563"
Claim: "p_1\\not=p_2"
The clain is either the null hypothesis or the alternative hypothesis. The null hypothesis states as an equality.
Since the null hypothesis is not the claim the alternative hypothesis is the claim.
The sample proportion is the number of successes divided by the sample size:
"x_2=\\hat{p_2}n_2=0.158(563)=88.954"
"\\hat{p_p}={x_1+x_2 \\over n_1+n_2}={93.104+88.954 \\over 529+563}\\approx0.1667"
The critical value at the 5% significance level
Determine the value of the test statistic:
"z={0.176-0.158 \\over \\sqrt{0.1667(1-0.1667)}\\sqrt{{1 \\over 529}+{1 \\over 563}} }\\approx0.7976"
"-1.96<0.7976<1.96"
There is not sufficient evidence to support the claim that the incidence rate of GI problems for those who consume olestra chips according to the experimental regimen differs from the incidence rate for the TG control group.
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