a) 6^3 = 216
b) let n be for the third time
n = 1 => P = 0
n = 2 => (1, 1) => P = 1/216
n = 3 => (1, 2) and (2, 1) => P = 2/216
n = 4 => (1,3), (3,1), (2,2) => P = 3/216
n = 5 => (1,4), (4,1), (2,3), (3,2) => P = 4/216
n = 6 => (1,5), (5,1), (2,4), (4,2), (3,3) => P = 5/216
TOTAL P = (1+2+3+4+5)/216 = 15/216
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