One sample t-test.
Null hypothesis H0: μ=78H_0:\;\mu=78H0:μ=78
Alternative hypothesis Ha: μ≠78H_a:\;\mu\neq78Ha:μ=78
Test statistic: t=xˉ−μsn=84−781617=1.55t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}}}=\frac{84-78}{\frac{16}{\sqrt{17}}}=1.55t=nsxˉ−μ=171684−78=1.55
Degrees of freedom: df=n−1=17−1=16df=n-1=17-1=16df=n−1=17−1=16
P-value: p=0.1407p=0.1407p=0.1407
Since the P-value is greater than 0.05, fail to reject the null hypothesis.
The difference is not consistent..
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