A box contains a certain no. of balls, on each of 60% balls A is marked and on each of 30% balls letter B is marked and on each of the remaining balls letter C idols marked . A ball is drawn at random, find the probability that the ball drawn is (1)marked C
(2)marked A or B
(3)marked neither B nor C
1
Expert's answer
2019-07-16T09:57:03-0400
(1) because the probability to get A ball 60% and B 30% C=100-30-60=10% => P(C)=0.1;
(2) P(A+B)=P(A)+P(B)=0.6+0.3=0.9;
(3) because all balls are marked then balls are not B and not C will be A=> P=P(A)=0.6.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment