"P(\\bar{X}>504)=P(Z>\\frac{504-500}{\\frac{25}{\\sqrt{100}}})=P(Z>1.6)=1-P(Z<1.6)=1-0.9452=0.0548."
Since the probability that a random sample of 100 filled boxes has the mean weight 504 g or more is greater than 0.05,
there is no reason to believe that machine is over filling the boxes.
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Dear Muhammad Fahad Fayyaz, please use the panel for submitting new questions.
The weights of packages filled by machine are normally distributed about a mean of 25 ounces, with a standard deviation of one ounce. What is the probability that n packages from the machine will have an average weight of less than 24 ounces if n = 1, 4, 16, 64? (10)
Dear Sean, please use the panel for submitting new questions.
The can filling machine was very accurate, with an average filling weight of 400g and a standard deviation of 20g. The operations manager takes a random sample of 50 cans and finds that the sample mean filling weight is 395g. a) What is the probability of obtaining a sample mean of 395g or less?
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