To get a solution assume that the number of flaws per unit area is Poisson distributed.
Let X be the Poisson random variable with the mean equal to E(X)=λS0S.
Formula Poisson probability
P(X=k)=k!(λS0S)k⋅e−(λS0S) Given that
λ=1,S0=50ft2,S=4ft⋅8ft=32ft2 Then
λS0S=1⋅50ft232ft2=0.64
a)
P(X=0)=0!0.640⋅e−0.64=e−0.64≈0.5273 b)
P(X≤1)=P(X=0)+P(X=1)=
0!0.640⋅e−0.64+1!0.641⋅e−0.64=e−0.64+0.64e−0.64=1.64e−0.64≈
≈0.8648
Comments