To get a solution assume that the number of flaws per unit area is Poisson distributed.
Let X be the Poisson random variable with the mean equal to "E(X)=\\lambda \\dfrac{S}{S_0}."
Formula Poisson probability
Given that
Then
a)
b)
"{0.64^0\\cdot e^{-0.64} \\over 0!}+{0.64^1\\cdot e^{-0.64} \\over 1!}=e^{-0.64}+0.64e^{-0.64}=1.64e^{-0.64}\\approx"
"\\approx0.8648"
Comments
Leave a comment