a. P(Z≤z∗)=0.92,P(Z>z∗)=0.08z∗=1.4051
b. P(Z≤z∗)=0.28,P(Z>z∗)=0.72z∗=−0.5828
c. P(Z≤z1∗)=0.5−0.29=0.21,P(Z<z2∗)=0.5+0.29=0.79
z∗=±0.8064 So the interval is (−0.8064,0.8064)
d. P(Z≤z1∗)=0.5−0.225=0.275,P(Z<z2∗)=0.5+0.225=0.725
z∗=±0.5978 So the interval is(−0.5978,0.5978).
Comments