Question #8610

Assume that the average annual salary for a worker in the United States is $35,000 and that the annual salaries for Americans are normally distributed with a standard deviation equal to 6,500. Find the following:

A-What percentage of Americans earn below $26,000.
B- What percentage of Americans earn below $26,000.

Expert's answer

E=35000\mathrm{E} = 35000D=6500\mathrm{D} = 6500


x- random variable- represents salary.


P(x<26000)=P(Exd<E26000d)=by Central Limit Thereme=F(35000260006500)=F(1.38)=0.9162\mathrm{P}(x < 26000) = \mathrm{P}\left(\frac{E - x}{d} < \frac{E - 26000}{d}\right) = \text{by Central Limit Thereme} = \mathrm{F}\left(\frac{35000 - 26000}{6500}\right) = \mathrm{F}(1.38) = 0.9162

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