Since it is stated that "the probability of 7 cars arriving [that is
"m"] in any given hour is three times higher than the
probability of 9 cars arriving [which is
"0.1"]", we can calculate that
"m=3P(X=9)=3\\cdot 0.1=0.3."However in this case the sum
"\\Sigma P(X)=0.3+0.2+0.3+0.2+0.1=1.1>1,"which means that this is not a valid probability distribution.
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