Question #82820

There are Forty houses in a housing estate. Twenty five of them have door-phones and 19 have door bells. If there is no house with either of the system. Find how many houses have both door bell and door-phone.

Expert's answer

Answer on Question #82820 – Math – Statistics and Probability

Question

There are Forty houses in a housing estate. Twenty five of them have door-phones and 19 have door bells. If there is no house with either of the system. Find how many houses have both door bell and door-phone.

Solution

P(A∪B)=P(A)+P(B)−P(A∩B).P(A \cup B) = P(A) + P(B) - P(A \cap B).P(A∩B)=P(A)+P(B)−P(A∪B)=2540+1940−4040=4440−1=0.1.P(A \cap B) = P(A) + P(B) - P(A \cup B) = \frac{25}{40} + \frac{19}{40} - \frac{40}{40} = \frac{44}{40} - 1 = 0.1.


Answer: 0.1.

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