Question #79096

A box contain three slips of paper marked 1,2,3 and in another box three slips of paper marked 4,5,6.One from each box is drawn.
a)Find the probability of both being odd?
b)find probability of atleast one odd?

Expert's answer

Answer on Question #79096 – Math – Statistics and Probability

Question

A box contain three slips of paper marked 1,2,3 and in another box three slips of paper marked 4,5,6. One from each box is drawn.

a) Find the probability of both being odd?

b) find the probability of at least one odd?

Solution

a) The probability that the first odd: p1=23p_1 = \frac{2}{3} (mark 1 or mark 3).

The probability that the second odd: p2=13p_2 = \frac{1}{3} (only mark 5).

Then the required probability is p=p1p2=29p = p_1p_2 = \frac{2}{9} .

b) the probability that both even: q=1323=29q = \frac{1}{3} \cdot \frac{2}{3} = \frac{2}{9} .

Then the required probability is p=1q=79p = 1 - q = \frac{7}{9}

Answer: a) p=29p = \frac{2}{9} , b) p=79p = \frac{7}{9} .

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