Question #7865

The average estimate for the body repair on an automobile is $1540. From insurance records it has been determined that the population standard deviation is $640.

A. What is the probability of selecting a sample of 49 and the sample mean being above $1600?

Expert's answer

Problem #7865 The average estimate for the body repair on an automobile is $1540. From insurance records it has been determined that the population standard deviation is $640. A. What is the probability of selecting a sample of 49 and the sample mean being above $1600?.

Solution Denote by ξi,i=1,49\xi_{i}, i = \overline{1,49} — the cost of automobile repair of ii-th customer. We are to estimate P(ξ1++ξ4949>1600)=P(ξ1++ξ4949640>160049/640)1Φ(1600/4480)0.363P\left(\frac{\xi_1 + \ldots + \xi_{49}}{49} > 1600\right) = P\left(\frac{\xi_1 + \ldots + \xi_{49}}{\sqrt{49} \cdot 640} > 1600\sqrt{49}/640\right) \approx 1 - \Phi(1600/4480) \approx 0.363. The approximate equality follows from CLT.

Answer 0.363.

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