Question #76898

Find the nearest neighbor statistic when n points are equidistant from one another on the circumference of a circle with a radius r, and there is one additional point located at the center of the circle. Assume that travel between neighboring points on the circumference can only occur along the circumference. Note that you can break the solution into two parts - one where the distance between neighboring points along the circumference is less than r, and the other where the distance is greater than or equal to r.
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Expert's answer

2018-05-04T09:12:07-0400

Answer on Question #76898 – Math – Statistics and Probability

Question

Find the nearest neighbor statistic when nn points are equidistant from one another on the circumference of a circle with a radius rr, and there is one additional point located at the center of the circle. Assume that travel between neighboring points on the circumference can only occur along the circumference. Note that you can break the solution into two parts - one where the distance between neighboring points along the circumference is less than rr, and the other where the distance is greater than or equal to rr.

Solution

The nearest neighbor statistic:


c=dˉ0dˉESEc = \frac{\bar{d}_0 - \bar{d}_E}{SE}


where dˉ0\bar{d}_0 is mean of observed nearest neighbor distances:


dˉ0=distn=2πrn\bar{d}_0 = \frac{\sum dist}{n} = \frac{2\pi r}{n}

dˉE\bar{d}_E is expected mean of nearest neighbor distances:


dˉE=0.5n/A=0.5n/πr2=0.5rπn\bar{d}_E = \frac{0.5}{\sqrt{n/A}} = \frac{0.5}{\sqrt{n/\pi r^2}} = \frac{0.5r\sqrt{\pi}}{\sqrt{n}}

SESE is the standard error of the mean of nearest neighbor distances:


SE=0.26136n2/A=0.26136rπnSE = \frac{0.26136}{\sqrt{n^2/A}} = \frac{0.26136r\sqrt{\pi}}{n}


Then:


c=2πrn0.5rπn0.26136rπn=2π0.261360.5n0.26136=13.561.91nc = \frac{\frac{2\pi r}{n} - \frac{0.5r\sqrt{\pi}}{\sqrt{n}}}{\frac{0.26136r\sqrt{\pi}}{n}} = \frac{2\sqrt{\pi}}{0.26136} - \frac{0.5\sqrt{n}}{0.26136} = 13.56 - 1.91\sqrt{n}


If the distance between neighboring points along the circumference is less than rr:


n=2÷6n = 2 \div 6c=10.86÷8.88c = 10.86 \div 8.88


If the distance between neighboring points along the circumference is greater than or equal to rr:


n>6n > 6c<8.88c < 8.88


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