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Answer to Question #76651 in Statistics and Probability for Hunter
Question #76651
there are 25 applications for four software tester positions
Expert's answer
If there are 25 applications for four software tester positions, then the number of possible combinations is:
C(25;4) = n!/(m!*(n - m)!) = 25!/(4!*(25 - 4)!) = 22*23*24*25/(1*2*3*4) = 22*23*25 = 12650.
C(25;4) = n!/(m!*(n - m)!) = 25!/(4!*(25 - 4)!) = 22*23*24*25/(1*2*3*4) = 22*23*25 = 12650.
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