Question #76493

About 1/5 of all adults in the United States have type O+ blood. If three randomly selected adults donate blood, find the probability of each of the following events . (round your answer to four decimal points)

A) All three are type O+
B) None of them are type O+
C) Two out of three are type O+

Expert's answer

Answer on Question #76493 – Math – Statistics and Probability

Question

About 1/5 of all adults in the United States have type O+ blood. If three randomly selected adults donate blood, find the probability of each of the following events. (round your answer to four decimal points)

A) All three are type O+

B) None of them are type O+

C) Two out of three are type O+

Solution

A)


P=151515=0.23=0.0080.P = \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} = 0.2^3 = 0.0080.


B)


P=(115)(115)(115)=0.83=0.5120.P = \left(1 - \frac{1}{5}\right) \left(1 - \frac{1}{5}\right) \left(1 - \frac{1}{5}\right) = 0.8^3 = 0.5120.


C)


P=(32)0.22(10.2)=30.040.8=0.0960.P = \binom{3}{2} \cdot 0.2^2 \cdot (1 - 0.2) = 3 \cdot 0.04 \cdot 0.8 = 0.0960.


Answer: A) 0.0080; B) 0.5120; C) 0.0960.

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