Question

When people were asked if they felt the laws covering the sale of firearms should be more strict, less strict, or kept as they are now, 54% responded more strict, 11% responded less, 34% said keep them as they are now, and 1% had no opinion. if 10 randomly selected people are asked the same question, what is the probability that 4 will respond more strict, 3 less, 2 keep the same, and i have no opinion?

Answer 1

First we have ten selected people.

With probability $P(A) = \frac{4}{10} * 0,54 = 0,216$ out of ten people four will respond more strict.

Since the probability $P(B) = \frac{3}{10} * 0,11 = 0,033$ out of ten people three will be responsible for less severe.

Since the probability $P(C) = \frac{2}{10} * 0,34 = 0,068$ out of ten people two will meet on leave the same.

Finally, I choose not to comply with the probability

$$P(D) = \frac{1}{10} * 0,01 = 0,001.$$

As we have events occurred together (A and B and C and D). It is this combination. We will have a formula for the probability of events N.

$$P(N) = P(A) * P(B) * P(C) * P(D) = 0,216 * 0,033 * 0,068 * 0,001 = 4,8 * 10^(-6)$$