Answer to Question #73531 in Statistics and Probability for Lee

Question

The probability that a randomly selected 3​-year-old male feral cat will live to be 4 years old is 0.69156. ​(a) What is the probability that two randomly selected 3​-year-old male feral cats will live to be 4 years​ old? (b) What is the probability that seven randomly selected 3​-year-old male feral cats will live to be 4 years​ old?

Answer 1

Actually the answer is 0.69156 to the power of n, where n is the number of randomly selected cats.
That is because we use AND relationship. It means a multiplication of probabilities.
In the case of 2 cats, we select the first cat and it will live to be 4 years with probability 0.69156, then we select second one.
It will live to be 4 years old with probability 0.69156. And resulting probability will be 0.69156 * 0.69156 = 0.47817
For the 7 cats the probability will be 0.69156*0.69156*0.69156*0.69156*0.69156*0.69156*0.69156=0.07560.