Answer for Question #71378
fX(x)=∫01(x+y)dy=x+21fY(y)=∫01(x+y)dx=y+21E[X]=∫01x(x+21)dx=127E[Y]=∫01y(y+21)dy=127E[XY]=E[X]E[Y]−KXY,KXY=∫01∫01xy(x+y)dydx=31E[XY]=(127)2−31=14449−14448=1441
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