Question #71163

A student commutes daily from his house to school. On average, the trip one way takes 24 minutes with a standard deviation of 3 minutes. Assume that the data is normally distributed. What is the probability that the trip will take more than half an hour
1

Expert's answer

2017-11-21T14:51:07-0500

Answer on Question #71163 – Math – Statistics and Probability

Question

A student commutes daily from his house to school. On average, the trip one way takes 24 minutes with a standard deviation of 3 minutes. Assume that the data is normally distributed. What is the probability that the trip will take more than half an hour.

Solution

In this dataset,


μ=24 and σ=3.\mu = 24 \text{ and } \sigma = 3.


We need to find the probability that the trip will take more than 30 minutes.

This is


P(T>30)=P(T24>3024)=P(T24>6)=P((T24)/3>6/3)=P((T24)/3>2).P(T > 30) = P(T - 24 > 30 - 24) = P(T - 24 > 6) = P((T - 24)/3 > 6/3) = P((T - 24)/3 > 2).


Now, if T follows N(24,9), then (T-24)/3 follows N(0,1), or the standard normal distribution.


P(T>30)=1(P((T24)/3<2)=1Φ(2),P(T > 30) = 1 - (P((T - 24)/3 < 2) = 1 - \Phi(2),


where Φ\Phi is the cumulative distribution function of the standard normal distribution.

From the standard normal distribution tables, we have


Φ(2)=0.97725.\Phi(2) = 0.97725.


Therefore,


P(T>30)=10.97725=0.02275.P(T > 30) = 1 - 0.97725 = 0.02275.


Answer: 0.02275.

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