Question #69902

Free range eggs are produced on a farm. The weights of eggs are found to be normally distributed with a mean of 55g and a standard deviation of 1g. Using the empirical rule and no calculations, determine whether it is likely a randomly chosen egg from the farm would have the following weight.



a. 51g
b. 53g
c. 56g
1

Expert's answer

2017-09-06T14:43:07-0400

Answer on Question #69902 – Math – Statistics and Probability

Question

Free range eggs are produced on a farm. The weights of eggs are found to be normally distributed with a mean of 55g and a standard deviation of 1g. Using the empirical rule and no calculations, determine whether it is likely a randomly chosen egg from the farm would have the following weight.

a. 51g

b. 53g

c. 56g

Solution

By the empirical rule,


P(μσ<X<μ+σ)=0.68,P(μ2σ<X<μ+2σ)=0.95,P(μ3σ<X<μ+3σ)=0.997.\begin{array}{l} P(\mu - \sigma < X < \mu + \sigma) = 0.68, \\ P(\mu - 2\sigma < X < \mu + 2\sigma) = 0.95, \\ P(\mu - 3\sigma < X < \mu + 3\sigma) = 0.997. \end{array}


So

a. P(X<51)=P(X<μ4σ)<P(X<μ3σ)<10.9972=0.0015P(X < 51) = P(X < \mu - 4\sigma) < P(X < \mu - 3\sigma) < \frac{1 - 0.997}{2} = 0.0015 – very unlikely.

b. P(X<53)=P(X<μ2σ)=10.952=0.025P(X < 53) = P(X < \mu - 2\sigma) = \frac{1 - 0.95}{2} = 0.025 – unlikely.

c. P(X>56)=P(X>μ+σ)=10.682=0.16P(X > 56) = P(X > \mu + \sigma) = \frac{1 - 0.68}{2} = 0.16 – not unlikely.

Answer: a. very unlikely; b. unlikely; c. not unlikely.

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