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Answer to Question #69226 in Statistics and Probability for jw
Question #69226
A certain disease is spread by only direct contact. The probability of a healthy person to get infect by a single direct contact is 0.02. What is the chance that a healthy person gets infected with the disease by the fourth time he comes into contact with an infected person. (assume contact with the other person is independent)
Expert's answer
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Comments
Thank you for correcting us. The value of 1-0.98^4 is the probability of being infected any time of the whole period when all four contacts occur. The value of 0.98^3*0.02 is the probability of being infected only the last fourth time a healthy person comes into contact with an infected person.
Some would compute it as 1 - 0.98^4 = 0.0776. What would be the difference? My school gives the solution as such.
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