Answer on Question #68723 – Math – Statistics and Probability
Question
Fit a normal curve to the following data
x: 2 4 6 8 10
f: 1 4 6 4 1
Solution
Probability density function: f=1σ2πe−(x−μ)22σ2=0.1927e−0.1172(x−6)2f = \frac{1}{\sigma\sqrt{2\pi}} e^{-\frac{(x - \mu)^2}{2\sigma^2}} = 0.1927e^{-0.1172(x - 6)^2}f=σ2π1e−2σ2(x−μ)2=0.1927e−0.1172(x−6)2 .
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