Question #68039

Let X has the discrete uniform distribution
f
(
x
)
=
1
k
f(x)=1k
for x=0,1,2…. , find the expression for its mean u
1

Expert's answer

2017-05-16T14:19:10-0400

Answer on Question #68039 - Math - Statistics and Probability

Question

Let XX has the discrete uniform distribution f(x)=1kf(x) = \frac{1}{k} for x=0,1,2x = 0,1,2\ldots, find the expression for its mean uu.

Solution

In *probability theory* and *statistics* by discrete uniform distribution we denote a *probability distribution* whereby a finite number of values are equally likely to be observed; every one of kk values has equal probability 1/k1 / k.

Therefore, the given distribution is the discrete uniform distribution, if we write


f(x)=1kfor x=0,1,2,,k1.f(x) = \frac{1}{k} \quad \text{for } x = 0,1,2,\ldots,k-1.


Then its mean is equal to


u=01k+11k+21k++(k1)1k=1k(0+1+2++k1).u = 0 \cdot \frac{1}{k} + 1 \cdot \frac{1}{k} + 2 \cdot \frac{1}{k} + \cdots + (k-1) \cdot \frac{1}{k} = \frac{1}{k} \cdot (0 + 1 + 2 + \cdots + k - 1).


In brackets we have a sum of arithmetic sequence. Therefore,


u=1k(0+k1)2k=k12.u = \frac{1}{k} \cdot \frac{(0 + k - 1)}{2} \cdot k = \frac{k - 1}{2}.


Answer: u=k12u = \frac{k - 1}{2}.

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