Question #68030

When you toss 5 coins once, if the number of head(s) is the random variable define on the resulting sample space. What is the set of random variable resulting from this experiment?
1

Expert's answer

2017-05-23T11:47:10-0400

Answer on Question #68030 - Math - Statistics and Probability

Question

When you toss 5 coins once, if the number of head(s) is the random variable define on the resulting sample space. What is the set of random variable resulting from this experiment?

Solution

When we toss five coins simultaneously, the corresponding sample space SS is


{HHHHH,HHHHT,HHHTH,HHTHH,HTHHH,THHHH,HHHTT,HHTHT,HTHHT,\{HHHHH, HHHHT, HHHTH, HHTHH, HTHHH, THHHH, HHHTT, HHTHT, HTHHT,THHHT,HHTTH,HTHTH,THHTH,HTTHH,THTHH,TTHHH,HHTTT,HTHTT,THHHT, HHTTH, \quad HTHTH, THHTH, HTTHH, THTHH, TTHHH, HHTTT, HTHTT,HTTHT,HTTTH,THHTT,THTHT,THTTH,TTHHT,TTHTH,TTHTH,HTTTT,THTTT,HTTHT, HTTTH, THHTT, THTHT, THTTH, TTHHT, TTHTH, TTHTH, HTTTT, THTTT,TTHTT,TTTHT,TTTTH,TTTTT},T T H T T, T T T H T, T T T T H, T T T T T \},


where HH is denoted for a head and TT is denoted for a tail.

The dimension of the sample space S=25=32|S| = 2^5 = 32.

If we denote by random variable XX the number of heads, then XX takes on the values {0,1,2,3,4,5}\{0,1,2,3,4,5\} with the corresponding probabilities


P{X=k}=(5k)(12)k(12)5k=(5k)(12)5,k{0,1,2,3,4,5}.P\{X = k\} = \binom{5}{k} \left(\frac{1}{2}\right)^k \left(\frac{1}{2}\right)^{5 - k} = \binom{5}{k} \left(\frac{1}{2}\right)^5, \quad k \in \{0,1,2,3,4,5\}.


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