Question #67665

Of 560 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of bacteria that cause​ food-borne illnesses, 65​% were infected with a particular bacterium.
​a) Construct a 90​% confidence interval.
​b) Explain what your confidence interval says about chicken sold in the country.
​c) A government spokesperson claimed that the sample size was too​ small, relative to the billions of chickens slaughtered each​ year, to generalize. Is this criticism​ valid?
1

Expert's answer

2017-05-04T13:58:08-0400

Answer on Question #67665 – Math – Statistics and Probability

Question

Of 560 broiler chickens purchased from various kinds of food stores in different regions of a country and tested for types of bacteria that cause food-borne illnesses, 65% were infected with a particular bacterium.

a) Construct a 90% confidence interval.

b) Explain what your confidence interval says about chicken sold in the country.

c) A government spokesperson claimed that the sample size was too small, relative to the billions of chickens slaughtered each year, to generalize. Is this criticism valid?

Solution

a) 90%CI=(0.651.6450.650.35560,0.65+1.6450.650.35560)=90\% CI = \left(0.65 - 1.645\sqrt{\frac{0.65*0.35}{560}},\,0.65 + 1.645\sqrt{\frac{0.65*0.35}{560}}\right) =

=(0.617,0.683).= (0.617,0.683).

b) We are 90% confident that between 61.7% and 68.3% of the chicken sold in the country were infected.

c) No. Until the necessary assumptions and conditions for the confidence interval are met, the results can be generalized.

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Comments

Assignment Expert
13.01.19, 22:33

To compute critical values one can apply the inverse of the standard normal distribution (for example, =NORM.S.INV(1-0.1/2) in Microsoft Excel). The 90% confidence interval will have the same critical values as a one-sample two-tailed z-test with alpha=0.1.

Tayor
13.01.19, 21:49

How did you get the 1.645 beacuse I tried InvT and I'm not quite sure what values to input?

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