Question

A research company polled a random sample of 834 teens about Internet use. 43​% of those teens reported that they had misrepresented their age online to gain access to websites and online services.Calculate the standard error of p

Answer 1

Answer on Question #67657 – Math – Statistics and Probability

Question

A research company polled a random sample of 834 teens about Internet use. 43% of those teens reported that they had misrepresented their age online to gain access to websites and online services. Calculate the standard error of p.

Solution

The standard error of sample proportions is denoted by $SE_p$ and it is given by the following formula

$$SE_p = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}$$

We have that

$$n = 834, \hat{p} = 0.43.$$

Then the standard error of p is

$$SE_p = \sqrt{\frac{0.43(1 - 0.43)}{834}} \approx 0.017143.$$

Answer: $SE_p = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \approx 0.017143.$

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