Answer on Question#65329 – Math – Statistics and Probability
Question. Find the mean and standard deviation of the following frequency distribution:
Total 300.
Solution. To find the mean and variation we shall construct the following auxiliary table
(see the similar example on http://www.statcan.gc.ca/edu/power-pouvoir/ch12/5214891-eng.htm):
For example, if we have interval 6.45 – 7.25 then midpoint for it is ______ etc. The mean is equal to . The variation is ______ — 7621.
Then standard deviation is equal to 33.
Answer. 33.
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