Question #65162

A student obtained the following results for the normality of a Nitric acid solution: 0.424; 0.528; 0.621; 0.433; 0.537. Should 0.621 as a result be rejected statistically?
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Expert's answer

2017-02-15T11:57:13-0500

Question #65162, Math / Statistics and Probability

A student obtained the following results for the normality of a Nitric acid solution: 0.424; 0.528; 0.621; 0.433; 0.537. Should 0.621 as a result be rejected statistically?

Answer.

Sample mean x=15i=15xi=0.5086\overline{x} = \frac{1}{5}\sum_{i=1}^{5}x_i = 0.5086 ;

Sample standard deviation s=14i=15(xix)2=0.0817s = \sqrt{\frac{1}{4}\sum_{i=1}^{5}(x_i - \overline{x})^2} = 0.0817 .


x+2s=0.6720>0.671.\overline{x} + 2s = 0.6720 > 0.671.


Thus, 0.621 should not be rejected statistically.

References.

Standard deviation. (2004, May 23). Retrieved February 8, 2017, from http://www.batesville.k12.in.us/physics/apphynet/Measurement/standard_deviation.htm

Mean, mode, median, and standard deviation. Retrieved February 10, 2017, from https://www.ltconline.net/greenl/courses/201/descstat/mean.htm

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