Question #64973

Let A and B be two events associated with an experiment such that 4 P(A) = 0. and
P(A ∪ B) = 0.7 . Compute ) P when (B
i) A and B are mutually exclusive.
ii) A and B are independent.
1

Expert's answer

2017-02-09T08:32:12-0500

Answer on Question #64973 – Math – Statistics and Probability

Question

Let A and B be two events associated with an experiment such that P(A)=0.4P(A) = 0.4 and P(AB)=0.7P(A \cup B) = 0.7.

Compute P(B)P(B) when

i) A and B are mutually exclusive;

ii) A and B are independent.

Solution

i) If events A and B are mutually exclusive [1], then


P(AB)=0.P(A \cap B) = 0.


The probability of the union of two events [2] is


P(AB)=P(A)+P(B)P(AB),P(A \cup B) = P(A) + P(B) - P(A \cap B),


hence


P(B)=P(AB)P(A)=0.70.4=0.3.P(B) = P(A \cup B) - P(A) = 0.7 - 0.4 = 0.3.


ii) If events A and B are independent [3], then


P(AB)=P(A)P(B).P(A \cap B) = P(A)P(B).


Next,


P(AB)=P(A)+P(B)P(AB)=P(A)+P(B)P(A)P(B),P(A \cup B) = P(A) + P(B) - P(A \cap B) = P(A) + P(B) - P(A)P(B),


hence


P(B)=P(AB)P(A)1P(A)=0.70.410.4=0.5.P(B) = \frac{P(A \cup B) - P(A)}{1 - P(A)} = \frac{0.7 - 0.4}{1 - 0.4} = 0.5.


Answer: i) 0.3; ii) 0.5.

References

1. CK-12. Basic Probability and Statistics Concepts. A full Course. Section 1.4: Mutually Exclusive events. Retrieved from http://www.ck12.org/book/CK-12-Basic-Probability-and-Statistics-Concepts-A-Full-Course/section/1.4/

2. CS 21/ Math 19- Course Notes. Section 6.2 Unions and Intersections. Retrieved from https://math.dartmouth.edu/archive/m19w03/public_html/Section6-2.pdf

3. CK-12. Basic Probability and Statistics Concepts. A full Course. Section 1.2: Independent Events and Sample Spaces. Retrieved from http://www.ck12.org/book/CK-12-Basic-Probability-and-Statistics-Concepts/section/1.2/

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