Question #64972

The amount of apples (in kg) produced per day by 10 orchards are given below:
218.2 179.5 207.3 224.3 213.7
199.7 184.7 194.4 203.5 185.4
Find the first four moments about the mean and the coefficient of kurtosis for the
above data.
1

Expert's answer

2017-02-04T23:23:10-0500

Answer on Question #64972 – Math – Statistics and Probability

Question

The amount of apples (in kg) produced per day by 10 orchards are given below:

218.2 179.5 207.3 224.3 213.7

199.7 184.7 194.4 203.5 185.4

Find the first four moments about the mean and the coefficient of kurtosis for the above data.

Solution

The mean [1, p. 31] is


xˉ=xin\bar{x} = \frac{\sum x_i}{n}


The mean is


218.2+179.5+207.3+224.3+213.7+199.7+184.7+194.4+203.5+185.410=201.07\frac{218.2 + 179.5 + 207.3 + 224.3 + 213.7 + 199.7 + 184.7 + 194.4 + 203.5 + 185.4}{10} = 201.07


The k-th moment about the mean [2] is


μk=(xixˉ)kn\mu_k = \frac{\sum (x_i - \bar{x})^k}{n}

1st1^{\text{st}} moment about the mean is


μ1=110[(218.2201.07)+(179.5201.07)+(207.3201.07)+(224.3201.07)+(213.7201.07)+(199.7201.07)+(184.7201.07)+(194.4201.07)+(203.5201.07)+(185.4201.07)]=0\begin{array}{l} \mu_1 = \frac{1}{10} \left[ (218.2 - 201.07) + (179.5 - 201.07) + (207.3 - 201.07) + (224.3 - 201.07) \right. \\ \left. + (213.7 - 201.07) + (199.7 - 201.07) + (184.7 - 201.07) \right. \\ \left. + (194.4 - 201.07) + (203.5 - 201.07) + (185.4 - 201.07) \right] = 0 \end{array}

2nd2^{\text{nd}} moment about the mean is


μ2=110[(218.2201.07)2+(179.5201.07)2+(207.3201.07)2+(224.3201.07)2+(213.7201.07)2+(199.7201.07)2+(184.7201.07)2+(194.4201.07)2+(203.5201.07)2+(185.4201.07)2]=206.2461\begin{array}{l} \mu_2 = \frac{1}{10} \left[ (218.2 - 201.07)^2 + (179.5 - 201.07)^2 + (207.3 - 201.07)^2 + (224.3 - 201.07)^2 \right. \\ \left. + (213.7 - 201.07)^2 + (199.7 - 201.07)^2 + (184.7 - 201.07)^2 \right. \\ \left. + (194.4 - 201.07)^2 + (203.5 - 201.07)^2 + (185.4 - 201.07)^2 \right] = 206.2461 \end{array}

3rd3^{\text{rd}} moment about the mean is


μ3=110[(218.2201.07)3+(179.5201.07)3+(207.3201.07)3+(224.3201.07)3+(213.7201.07)3+(199.7201.07)3+(184.7201.07)3+(194.4201.07)3+(203.5201.07)3+(185.4201.07)3]=126.3489\begin{array}{l} \mu_3 = \frac{1}{10} \left[ (218.2 - 201.07)^3 + (179.5 - 201.07)^3 + (207.3 - 201.07)^3 + (224.3 - 201.07)^3 \right. \\ \left. + (213.7 - 201.07)^3 + (199.7 - 201.07)^3 + (184.7 - 201.07)^3 \right. \\ \left. + (194.4 - 201.07)^3 + (203.5 - 201.07)^3 + (185.4 - 201.07)^3 \right] = 126.3489 \end{array}

4th4^{\text{th}} moment about the mean is


μ4=110[(218.2201.07)4+(179.5201.07)4+(207.3201.07)4+(224.3201.07)4+(213.7201.07)4+(199.7201.07)4+(184.7201.07)4+(194.4201.07)4+(203.5201.07)4+(185.4201.07)4]=75485.5925\begin{array}{l} \mu_ {4} = \frac {1}{10} \left[ (218.2 - 201.07) ^ {4} + (179.5 - 201.07) ^ {4} + (207.3 - 201.07) ^ {4} + (224.3 - 201.07) ^ {4} \right. \\ \left. + (213.7 - 201.07) ^ {4} + (199.7 - 201.07) ^ {4} + (184.7 - 201.07) ^ {4} \right. \\ \left. + (194.4 - 201.07) ^ {4} + (203.5 - 201.07) ^ {4} + (185.4 - 201.07) ^ {4} \right] \\ = 75485.5925 \end{array}


The coefficient of kurtosis [3, p. 3] is


μ4μ22\frac {\mu_ {4}}{\mu_ {2} ^ {2}}


The coefficient of kurtosis is


μ4μ22=75485.5925206.24612=1.7746\frac {\mu_ {4}}{\mu_ {2} ^ {2}} = \frac {75485.5925}{206.2461 ^ {2}} = 1.7746

References:

1. Saylor Academy open textbook. Introductory statistics textbook. Retrieved from https://www.saylor.org/site/textbooks/Introductory%20Statistics.pdf.

2. Central Moment. An R Introduction to Statistics. Retrieved from http://www.r-tutor.com/elementary-statistics/numerical-measures/moment.

3. Sharon I. O'Donell. Notes – Econ 2370 – Statistics and Probability. Retrieved from http://www.uh.edu/~odonnell/econ2370/moment.pdf.

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